Question

ayuda con este ejercicio.es urgenteeeee

Answer 1

(x-3)(2x+1) = 3 - x

$2x^{2} +x-6x-3 = 3-x$

$2x^{2} -5x - 3 = 3-x$

$2x^{2} -5x + x - 3 - 3 = 0$

$2x^{2} -4x - 6 = 0$

$x^{2} -2x - 3 = 0$
x                  -3
x                 +1

-3x + x = -2x

(x-3)(x+1) = 0

x-3 = 0      x+1 = 0
x = 3          x = -1

CS = (-1; 3)

Answer 2

2x^2 + x - 6x - 3 = 3 - x ( donde " 2x^2" es igual a decir; 2x elevado al cuadrado)

2x^2 - 5x = 6 - x

2x^2 - 5x + x = 6

2x^2 - 4x = 6

2x^2 - 4x - 6 = 0 ( sacamos mitad a todos los terminos)

x^2 - 2x - 3 = 0
x -3
x +1

x - 3 = 0 v x + 1 = 0
x = 3 x = -1

C.S = { 3, -1}