Question

(×-½)(×+⅓) ayuda con esta pregunta cuadratica nose como aserla

Answer 1

SOLUCIÓN

♛ HØlα!! ✌

Recordemos que por propiedad distributiva tenemos que

                   $\boxed{\boldsymbol{(a+b)(c+d) = ac + bc+bc+bd}}$

Entonces

               $(x-\dfrac{1}{2})(x+\dfrac{1}{3})=x(x)+x\left(\dfrac{1}{3}\right)-\left(\dfrac{1}{2}\right)x-\left(\dfrac{1}{2}\right)\left(\dfrac{1}{3}\right)\\\\\\(x-\dfrac{1}{2})(x+\dfrac{1}{3})=x^2+\dfrac{x}{3}-\dfrac{x}{2}-\dfrac{1}{6}\\\\\\(x-\dfrac{1}{2})(x+\dfrac{1}{3})=x^2+\dfrac{2x-3x}{6}-\dfrac{1}{6}\\\\\\\boxed{\boxed{\boldsymbol{(x-\dfrac{1}{2})(x+\dfrac{1}{3})=x^2-\dfrac{x}{6}-\dfrac{1}{6}}}}$