Question

AYUDA CON EL PROBLEMA E porfavorrr :c

Answer 1

Respuesta:

a) x = 2

b)  x = 12

c) x = 1/5

d) x = 1

e) x = 3/4

f) x = 2

Explicación:

a)

$x^2-1=\left(x+1\right)^2-3x$

$Calculamos \left(x+1\right)^2-3x:\quad x^2-x+1$

$x^2-1=x^2-x+1$

$x^2=x^2-x+2$

$x^2-\left(x^2-x\right)=x^2-x+2-\left(x^2-x\right)$

$x=2$

b)

$2x+5=3x-7$

$2x+5-5=3x-7-5$

$2x=3x-12$

$-x=-12$

$x=12$

c)

$\frac{2}{3}\left(x-2\right)-\frac{1}{4}\left(x-5\right)=$

$\frac{2}{3}x-2\cdot \frac{2}{3}-\frac{1}{4}\left(x-5\right) =$

$\frac{2}{3}x-2\cdot \frac{2}{3}-\frac{1}{4}x+5\cdot \frac{1}{4} =$

$\frac{-1+5x}{12} =$

$5x = 1\\x= \frac{1}{5}$

d)

$3x-5\left(x-2\right)=8$

$3x-5x+10=8$

$-2x+10=8$

$-2x=-2$

$x=1$

e)

$\frac{3x-1}{x-2}=\frac{3x-7}{x+4}$

$\left(3x-1\right)\left(x+4\right)=\left(x-2\right)\left(3x-7\right)$

$3x^2+11x-4=3x^2-13x+14$

$3x^2+11x=3x^2-13x+18$

$24x=18$

$x=\frac{3}{4}$

f)

$\frac{3x-4}{2}=\frac{5-x}{3}$

$\left(3x-4\right)\cdot \:3=2\left(5-x\right) =$

$9x-12=10-2x$

$9x=-2x+22$

$11x=22$

$x=2$