Question

Ayuda con el a, por favor

Answer 1

a.   Zn + 2HCl → ZnCl2 + H2↑

b. Mm Zn = 65.39 g/mol

calcular moles de Zn  aplicando la fórmula n = masa/Mm

n = 60 g / 65.39 g/mol

n = 0.918 moles Zn

calcular  Volumen de HCl

V HCl = 0.918 mol Zn  x  2 mol HCl   x  1 L HCl
                                       ````````````````   ``````````````
                                         1 mol Zn      3 mol HCl

V HCl = 0.612 Litros

V HCl = 0.612 x 1000 = 612 mL

B. calcular V de hidrógeno

1. calcular moles de H2

mol H2 = 0.918 mol Zn x 1 mol H2
                                        ``````````````
                                         1 mol Zn

mol H2 = 0.918

2. aplicar Ley general de los Gases

V · P = n · R · T

P = 1 atm
n = 0.918 mol H2
T = 298 K
R = 0.082 (L atm / mol K )

V = 0.918 moles · 0.082 (L atm / mol K) · 298 K
      ``````````````````````````````````````````````````````````````
                              1 atm

V = 22.43 Litros

d)     Zn     + 2HCl         →     ZnCl2    +  H2
 (65.39 g) +  2(36.45 g)→ (136.29 g)  + (2 g)
           65.39 g + 72.9 g = 136.29 g + 2 g
                       138.29 g = 138.29 g
 
se cumple la ley de la conservación de la masa