Matemáticas, pregunta formulada por arelioviedo360, hace 11 meses

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Adjuntos:

Respuestas a la pregunta

Contestado por adrysilveyra
1

Respuesta:

a^2-b^3= (-2)^2-5^3= 4-125=121

0,5a+0,3b= 5/10*(-2) + 3/10*5 =-2 + 3/2= 7/2= 3,5

3/5a - 7/10b = 3/5*(-2) - 7/10*5= -6/5- 7/2= -47/10

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a^2-b^3= (1/10)^2- (1/5)^3 =1/100-1/125 = 18/100=9/50

1/2*1/10+3/10*1/5= 1/20+3/50=110/1000=11/100

3/5*1/2-7/10*1/5= 3/10- 7/50=50/500=5/50=1/10

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a=3/4 b=-1/3

(3/4)^2-(-1/3)^3=9/16+1/27=227/432

0,5*3/4-7/10*(-1/3)=3/8+7/30= 73/120

3/5*3/4 -7/10*(-1/3)= 9/20+7/30= 41/60

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a=0 b=-1

0^2-(-1)^3=0+1=1

0,5*0+0,3*(-1)=0+0,3=0,3

0,5*0+7/10*(-1)=0-7/10=-7/10

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a=-4 b= -3

(-4)^2+(-3)^3=16-27=-11

0,5*(-4)+ 0,3*('3)=-2+9/10=29/10

3/5*(-4)-7/10*(-3)=-12/5+21/10=49/10=4,9

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a=1/2 b=0

(1/2)^2+0^3=1/4+0=1/4

1/2*1/2+3/10*0=1/4+0=1/4

3/5*1/2 - 7/10*0= 3/10+0=3/10

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a=-0,2 b=0,2

(-1/5)^2 - (1/5)^3=1/25-1/125=4/125

1/2*(-1/2) + 3/10*1/5=-1/4+3/50=62/150=31/75

3/5*(-1/5) - 7/10*1/5=-3/25-7/50=-1/50

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a=5 b=10

5^2- 10^3=25 - 1000=775

0,5*5+0,3*10=2,5+3=5,5=55/10=11/2

3/5*5-7/10*10= 3-7= -4

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