Question

ayuda a resolves esto de numeros complejos!!
1. Sumar
a) ( 4 + 2i ) + ( 2 + 3i ) =
b) ( -1 + i ) + ( 2 - i ) =
c) ( 1 - √2i ) + ( - 2 + 3√2i ) =
d) ( 2/5 - 3i ) + ( 7/10 - 3i ) =
2. Restar
a) ( 3 + 4i ) - ( 1 + 3i ) =
b) - 1/3i - ( 1/2 - 3/5i ) =
c) ( 1/5 + 3/2i ) - ( 9 - 3i ) =
d) ( - 1/3 + 2/3i ) - ( 5/6 - i ) =

Answer 1

Respuesta:

1. Sumar

a) ( 4 + 2i ) + ( 2 + 3i ) =  6+ 5i

b) ( -1 + i ) + ( 2 - i ) =  1

c) ( 1 - √2i ) + ( - 2 + 3√2i ) =-1+3

d) ( 2/5 - 3i ) + ( 7/10 - 3i ) = 11/10 -6i

2. Restar

a) ( 3 + 4i ) - ( 1 + 3i ) =  2+1i

b) - 1/3i - ( 1/2 - 3/5i ) =  -1/2+4/15i

c) ( 1/5 + 3/2i ) - ( 9 - 3i ) = -44/5+9/2i

d) ( - 1/3 + 2/3i ) - ( 5/6 - i ) =-7/6+5/3i

Explicación paso a paso: