Question

................................................................ayuda...............

Answer 1

Respuesta:

0

Explicación paso a paso:

$\frac{3}{4}x^4y^5-\frac{6}{8}x^4y^5+\frac{1}{2}x^4y^5-\frac{2}{4}x^4y^5$

$=x^4y^5\left(\frac{3}{4}-\frac{6}{8}+\frac{1}{2}-\frac{2}{4}\right)$

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$\frac{3}{4}-\frac{6}{8}+\frac{1}{2}-\frac{2}{4}$

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$=\frac{3-2}{4}$

$=\frac{1}{4}$

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$=\frac{1}{4}-\frac{6}{8}+\frac{1}{2}$

$=\frac{1}{4}-\frac{3}{4}+\frac{1}{2}$

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$=\frac{1-3}{4}$

$=-\frac{2}{4}$

$=-\frac{1}{2}$

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$=-\frac{1}{2}+\frac{1}{2}$

$=\frac{-1+1}{2}$

$=0$

Answer 2

Respuesta:

0

Explicación paso a paso:

Factorizar lo común

$x^{4}y^{5} ( \frac{3}{4} - \frac{6}{8} + \frac{1}{2} - \frac{2}{4} )$

$x^{4}y^{5} ( \frac{1}{4} -\frac{6}{8} +\frac{1}{2} )\\\\x^{4}y^{5} (\frac{1}{4} -\frac{6}{8} + \frac{1}{2} *\frac{4}{4} )\\\\x^{4}y^{5} (\frac{1}{4} - \frac{6}{8} +\frac{4}{8})\\\\x^{4}y^{5} (\frac{1}{4} - \frac{2}{8} )\\\\x^{4}y^{5} (\frac{1}{4} - \frac{1}{4} )\\\\x^{4}y^{5} (0 )\\\\0$

Ponle corona