Question

ay esta la respuesta

Answer 1

$\leq \alpha \sqrt{x} \frac{x}{y} \frac{x}{y} \leq \leq \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \frac{x}{y} \sqrt[n]{x} \sqrt[n]{x} \sqrt{x} x^{2} x^{2} \alpha \beta \leq \leq \leq x_{123} \frac{x}{y} \sqrt[n]{x} \sqrt{x}$