Question

auxilio ayúdenme a resolver estos ejercicios de elevar el cuadradode los siguientes binomios:
(a-2)=
(x+5)=
(6f+2g)=
(8h-4)=
(3a+5b)=
(9h2-2y2)
(-10x2+2y3)=
(-11m3-3m2)=
(10a2-5b3)=
(m+n)2=
(3x-4)2=
(-7m-3)2=
(9t+8)2=

Answer 1

Respuesta:

Se indica abajo.

Explicación paso a paso:

Todos los binomios al cuadrado presentan el siguiente resultado:

(a+b)² = a² + 2ab + b²

(a-b)² = a - 2ab + b²

(-a-b)² = a² + 2ab + b²

entonces:

(a-2)² = a² - 2*a*2 + 2² = a² -4a + 4

(x+5)² = x² + 2*x*5 + 5² = x² + 10x + 25

(6f+2g)² = (6f)² + 2*6f*2g + (2g)² = 36f² + 24fg + 4g²

(8h-4)² = (8h)² - 2*8h*4 + 4² = 64h -6ah + 16

(3a+5b)² = (3a)² + 2*3a*5b + (5b)² = 9a² + 30ab + 25b²

(9h²-2y²)² = (9h²)² - 2*9h²*2y² + (2y²) = 81h⁴ - 36h²y² + 4y²

(-10x²+2y³)² = (2y³-10x²) = (2y³)² - 2*2y³*10x² + (10x²)² = 4y⁶ - 40y³x² + 100x⁴

(-11m³-3m²)² = (11m³)² + 2*11m³*3m² + (3m²)² = 121m⁶ + 66m⁵ + 9m⁴

(10a²-5b³)² = (10a²)² - 2*10a²*5b³ + (5b³)² = 100a⁴ - 100a²b³ + 25b⁶

(m+n)² = m² + 2*m*n + n² = m² + 2mn + n²

(3x-4)² = (3x)² - 2*3x*4 + 4² = 9x² -24x + 16

(-7m-3)² = (7m)² + 2*7m*3 + 3² = 49m² + 42m + 9

(9t + 8)² = (9t)² + 2*9t*8 + 8² = 81t² + 144t + 64  

Answer 2

Respuesta:

• (a – 2)² = ${a}^{2} - 4a + 4$
• (x + 5)² = ${x}^{2} + 10x + 25$
• (6f + 2g)² = $36 {f}^{2} + 24fg + 4 {g}^{2}$
• (8h – 4)² = $64{h}^{2} - 64h + 16$
• (3a – 5b)² = $9 {a}^{2} + 30ab + 25 {b}^{2}$
• (9h² – 2y²)² = $81 {h}^{4} - 36 {h}^{2} {y}^{2} + 4 {y}^{4}$
• (– 10x² + 2y³)² = $100 {x}^{4} - 40 {x}^{2} {y}^{3} + 4 {y}^{6}$
• (– 11m³ – 3m²)² = $121 {m}^{6} + 66 {m}^{5} + 9 {m}^{4}$
• (10a² – 5b³)² = $100 {a}^{4} - 100 {a}^{2} {b}^{3} + 25 {b}^{6}$
• (m + n)² = ${m}^{2} + 2 mn + {n}^{2}$
• (3x – 4)² = $9 {x}^{2} - 24x + 16$
• (– 7m – 3)² = $49 {m}^{2} + 42m + 9$
• (9t + 8)² = $81 {t}^{2} + 144 t + 64$