Question

áreas de regiones circulares
ayuda porfas en estos ejercicios​

Answer 1

Respuesta:

Explicación paso a paso:

2 )

$Radio: r =\sqrt{5} m$

$\pi =3.14$

$Area: A = ?$

$Formula:$

$A = \pi r^{2}$

$A = \pi (\sqrt{5} m)^{2} = \pi (5m^{2} )$

$A = 5\pi m^{2}$

$A = 5(3.14) m^{2}$

$A = 15.7m^{2}$

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3 )

$Area: A = 16m^{2}$

$\pi = 3.14$

$Radio:R =?$

$Formula:$

$R = \sqrt{\frac{A}{\pi } }$

$R = \sqrt{\frac{16m^{2} }{3.14} }$

$R = \sqrt{5.1m^{2} }$

$R = 2.26m$

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4 )

$Radio: R = 6m$

$\pi =3.14$

$Area -de-la -region -sombreada: A s = ?$

$Formula:$

$As = \frac{\pi R^{2} }{2}$

$As = \frac{(3.14)(6m)^{2} }{2} =\frac{(3.14)(36m^{2}) }{2} =\frac{113.04m^{2} }{2}$

$As = 56.52m^{2}$

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7 )

$Radio: R = 4u$

$\pi =3.14$

$Area -de-la-region -sombreada: As = ?$

Fórmula:

$As = \frac{\pi R^{2} }{4}$

$As = \frac{\pi (4u)^{2} }{4} =\frac{(3.14)(16u^{2}) }{4} =(3.14)(4u^{2} )$

$As= 12.56u^{2}$