Question

Aplicar propiedad distributiva

(x+5) (x+7)=
(2x-3) (5x+1)=
(x-2) (4x-5)=
4(2x²+5x-4)=

Answer 1

(x+5)(x+7)= x²+7x+5x+35= x²+12x+35

(2x-3)(5x+1)= 10x²+2x-15x-3= 10x²-13x-3

(x-2)(4x-5)= 4x²-5x-8x+10= 4x²-13x+10

4(2x²+5x-4)=8x²+20x-16