Question

Aplicando la ley de Senos resuelve el triángulo donde B=65ª  b=17m  A=53ª

 

​

Answer 1

$\frac{a}{ \sin( \alpha ) } = \frac{b}{ \sin( \beta ) }$

$a = \frac{17( \sin(53) )}{ \sin(65) } = \frac{13.576m}{0.9063} = 14.979$

$\gamma = 180 - 65 - 53 = 62$

$\frac{c}{ \sin( \gamma ) } = \frac{b}{ \sin( \beta ) }$

$c = \frac{17( \sin(62)) }{ \sin(65) } = \frac{15.010m}{0.9063} = 16.561 \: m$