Question

An elastic circular conductor expands at a constant rate over time So its radius is given by r(t) = r0 + vt, where r0 = 0.100 m and v = 0.0150 m/s. The loop has a constant resistance of r = 12.0 for and is Placed in a uniform magnetic field of magnitude b0 = 0.750 t, Perpendicular to its plane, as it appears in the figure. Calculate the address and The magnitude of the induced current, I, at t = 5.00 s.​

Answer 1

Respuesta:

I = 1.03083 x 10⁻³ A

Explicación:

I = e/R

I = 2(0.750 t) π ( ( 0.100 m) + ( 0.0150 m/s)(5.00 s) )( 0.0150 m/s) / 12.0

I = ( 2(0.750) π ( ( 0.100) + ( 0.0150 )(5.00) )( 0.0150 ) )/ 12.0

I = 0.00103 A

I = 1.03083 x 10⁻³ A