Question

an = ( 2n + 1 )2 Hallar los primeros 5 terminos, dada la ley de formacion

Answer 1

Respuesta:

Explicación paso a paso:

Ley de formación:

$a_{n} = (2n + 1)^{2}$

Entonces n=1:

$a_{1} = (2(1) + 1)^{2}\\ a_{1} = (2 + 1)^{2}\\a_{1} = (3)^{2}\\a_{1} = 9$

Entonces n=2:

$a_{2} = (2(2) + 1)^{2}\\ a_{2} = (4 + 1)^{2}\\a_{2} = (5)^{2}\\a_{2} = 25$

Entonces n=3:

$a_{3} = (2(3) + 1)^{2}\\ a_{3} = (6 + 1)^{2}\\a_{3} = (7)^{2}\\a_{3} = 49$

Entonces n=4:

$a_{4} = (2(4) + 1)^{2}\\ a_{4} = (8 + 1)^{2}\\a_{4} = (9)^{2}\\a_{4} = 81$

Entonces n=5:

$a_{5} = (2(5) + 1)^{2}\\ a_{5} = (10 + 1)^{2}\\a_{5} = (11)^{2}\\a_{5} = 121$