Question

alla el balor de p (2p+20)+12=p+(40+5)​

Answer 1

Respuesta:

Explicación paso a paso:

p(2p+20)+12 = p+(40+5)

p(2p)+p(20)+12 = p + 45

2p^2+20p+12= p+45

2p^2+20p-p+12-45= 0

2p^2+19p-33 = 0

Factorizamos en aspa:

p +11

2p -3

(p +11) ( 2p -3) = 0

 Igualamos cada factor a cero:

p+11= 0

p = -11

2p-3 = 0

2p = 3

p = 3/2

CS ={-11, 3/2}