Question

Alguien sabe hacerlo ? Como es ? √6/ (√3-√2)

Answer 1

Racionalizar:

$\frac{\sqrt{6}}{\sqrt{3}-\sqrt{2}} = \frac{\sqrt{6}}{\sqrt{3}-\sqrt{2}} * \frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}}$

$\frac{\sqrt{6}}{\sqrt{3}-\sqrt{2}} = \frac{\sqrt{6} (\sqrt{3}+\sqrt{2})}{3-2} \ \ \boxed{\frac{\sqrt{6}}{\sqrt{3}-\sqrt{2}} =\sqrt{6} (\sqrt{3}+\sqrt{2}) = 3 \sqrt{2} +2 \sqrt{3} }$

Saludos!

Answer 2

un gusto espero que te sirva :)