Alguien que me ayude!!?
Reducir los siguientes polinomios:
a) P(x) = 8x2 – 3x3 + x – 5x2 – x3
b) Q(x) = -3 + 12x4 – x5 +x3 + x5 – 9x4 – 2
c) R(x) = (8/3)x4 – 4x2 – 6x4 + 3x2 – (1/2)x4 -1
d) S(x) = x2 + 22x4 – 7x3 – 4 + 8x + x4 + x2 – 9x3
e) T(x)= 5x4 – 3x3 + 9 + (2/5)x3 + 2x3 – 2 – (1/5)x4
f) U(x)= 13 + (9/7)x2 – 8 + 2x – (3/5)x2 – 9x – 7 – (4/7)x2
Respuestas a la pregunta
Respuesta:
a) P(x) = x( 3x - 4x³ + 1)
b) Q(x) = 3x4 + x3 - 5
c) R(x) = 8/3x4 + 2x2 - 1
d) S(x) = 23x4 - 16x3 + 2x2 + 8x - 4
e) T(x) = 24/5x4 + 5x3 + 7
f) U(x) = 4/35x2 - 7x - 2
Explicación paso a paso:
a) P(x) = 8x2 – 3x3 + x – 5x2 – x3
P(x) = 3x² - 4x³ + x
P(x) = x ( 3x - 4x³ + 1)
b) Q(x) = -3 + 12x4 – x5 +x3 + x5 – 9x4 – 2
Q(x) = 3x4 + x3 - 5
c) R(x) = (8/3)x4 – 4x2 – 6x4 + 3x2 – (1/2)x4 -1
R(x) = 8/3 x4 - 6x4 - 1/2x4 - x2 + 3x2 - 1
R(x) = (16x4 - 36x4 - x4) / 6 + 2x2 -1
R(x) = 16x4 / 6 + 2x2 - 1
R(x) = 8/3 x4 + 2x2 - 1
d) S(x) = x2 + 22x4 – 7x3 – 4 + 8x + x4 + x2 – 9x3
S(x) = 23x4 - 16x3 + 2x2 + 8x - 4
e) T(x)= 5x4 – 3x3 + 9 + (2/5)x3 + 2x3 – 2 – (1/5)x4
T(x) = 24/5 x4 +5x3 + 7
f) U(x)= 13 + (9/7)x2 – 8 + 2x – (3/5)x2 – 9x – 7 – (4/7)x2
U(x) = 9/7 x2 - 3/5x2 - 4/7x2 + 2x - 9x +13 - 8 - 7
U(x) = 5/7x2 - 3/5x2 - 7x - 2
U(x) = (25x2 - 21x2)/35 - 7x - 2
U(x) = 4x2/35 -7x - 2