Question

alguien que me ayude con trigonometría, por favor no entiendo nada:( y lo tengo que entregar mañana por favor ​

Answer 1

Explicación paso a paso:

Formulas

$sen = \frac{opuesto}{hipotenusa} = \frac{o}{h} \\ \\ coseno = \frac{adyacente}{hipotenusa} = \frac{a}{h} \\ \\ tangete = \frac{opuesto}{adyacente} = \frac{o}{a}$

Se deben ir despejando las fórmulas dependiendo el lado que necesites

26.

A

$a = \frac{o}{ \tan} = \frac{12}{ \tan(60) } = 6.92 \: cm$

B

$h = \frac{o}{sen} = \frac{12}{ \sin(60) } = 13.85 \: cm$

27.

A

$h = \frac{o}{sen} = \frac{24}{ \sin(50) } = 31.32 \: cm$

B

$a = \frac{o}{tan} = \frac{24}{ \tan(50) } = 20.13 \: cm$

28.

A

$o = a \tan = (15)( \tan(30) ) = 8.66 \: cm$

B

$h = \frac{a}{cos} = \frac{15}{ \cos(30) } = 17.32 \: cm$

29.

A

$a = h \:cos = (3)( \cos(36) ) = 2.42 \: cm$

B

$o = h \: sen = (3)( \sin(36) ) = 1.76 \: cm$

30.

A

$a = h \: cos = (61)( \cos(42) ) = 45.33 \: cm$

B

$o = h \: sen = (61)( \sin(42) ) = 40.81 \: cm$

31.

A

$o = a \: tan = (35)( \tan(40) ) = 29.36 \: cm$

B

$h = \frac{a}{cos} = \frac{35}{ \cos(40) } = 45.68 \: cm$

32.

A

$a = h \: cos = (29)( \cos(40) ) = 22.21 \: cm$

B

$o = h \: sen = (29)( \sin(40) ) = 18.64 \: cm$

33.

A

$a = \frac{o}{tan} = \frac{6}{ \tan(37) } = 7.96 \: cm$

B

$h = \frac{o}{sen} = \frac{6}{ \sin(37) } = 9.96 \: cm$

34.

A

$h = \frac{a}{cos} = \frac{28}{ \cos(30) } = 32.33 \: cm$

B

$o = a \: tan = (28)( \tan(30) ) = 16.16 \: cm$

35.

A

$a = h \: cos = (26)( \cos(56) ) = 14.53 \: cm$

B

$o = h \: sen = (26)( \sin(56) ) = 21.55 \: cm$

36.

A

$o = h \: sen = (50)( \sin(60) ) = 43.30 \: cm$

B

$a = h \: cos = (50)( \cos(60)) = 25 \: cm$

37.

A

$a = \frac{o}{tan} = \frac{10}{ \tan(45) } = 10 \: cm$

B

$h = \frac{o}{sen} = \frac{10}{ \sin(45) } = 14.14 \: cm$