Question

Alguien que me ayude​

Answer 1

x = 6

y = 8

z = 5

t = 2

$\frac{7x - 22}{2} + \frac{x + 6}{4} + x + x + 1 = 26$

$\frac{2(7x - 22) +x + 6 }{4} + 2x + 1 = 26$

$\frac{14x - 44 + x + 6}{4} + 2x + 1 = 26$

$\frac{4(2x + 1) +15x - 38}{4} = 26$

$8x + 4 + 15x - 38 = 26 \times 4$

$23x - 34 = 104$

$23x = 104 + 34$

$23x = 138$

$x = \frac{138}{23}$

$x = 6$

3y-2/2 + x + 5y - 8/8 + y - 3 = 26

$\frac{3y - 2}{2} + 6 + \frac{5y - 8}{8} + y - 3 = 26$

$\frac{3y - 2}{2} + \frac{5y - 8}{8} + y = 26 - 3$

$\frac{4(3y - 2) +5y - 8 + 8y}{8} = 23$

$12y - 8 + 5y - 8 + 8y = 23 \times 8$

$25y - 16 = 184$

$25y = 184 + 16$

$25y = 200$

$y = \frac{200}{25}$

$y = 8$

$x + 1 + \frac{3z + 3}{2} + z + 3 + \frac{z + 3}{4} = 26$

6+1 + (3z + 3)/2 + z+3 + (z+3)/4 = 26

7 + (3z + 3)/2 + (z+3)/4 + z+3 = 26

7 + (2(3z+3) + (z+3))/4 + z+3 = 26

7 + (6z+6+z+3)/4 + z+3 = 26

7 + (6z+6+z+3+4z+12)/4 = 26

(11z + 21)/4 = 26 - 7

(11z+21)/4 = 19

11z+21 = 76

11z = 76 - 21

11z = 55

z = 55/11

z = 5

y-3 + z+3 + 7t+10/2 + t-1 = 26

8 - 3 + 5 + 3 + 7t+10/2 + t - 1 = 26

$13 + \frac{7t + 10}{2} + t - 1 = 26$

$\frac{7t + 10}{2} + t - 1 = 26 - 13$

$\frac{7 t + 10 + 2(t - 1)}{2} = 13$

$7t + 10 + 2t - 2 = 13 \times 2$

$9t + 8 = 26$

$9t = 26 - 8$

$9t = 18$

$t = \frac{18}{9}$

$t = 2$

Comprobación:

x+1 + z+3 +3z+3/2+z+3/4 = 26

6+1+5+3+(3(5)+3)/2 + (5+3)/4 = 26

7 + 8 + 18/2 + 8/4 = 26

15 + 9 + 2 = 26

24 + 2 = 26

26 = 26

y-3+z+3+7t+10/2+t-1= 26

8-3+5+3+(7(2)+10)/2+2-1 = 26

5+8 + 24/2 + 1 = 26

13 + 12 + 1 = 26

25 + 1 = 26

26=26

3y-2/2 + 5y-8/8 + x + y-3 = 26

(3(8)-2)/2 + (5(8)-8)/8 + 6 + 8-3 = 26

(24-2)/2 +(40-8)/8 + 6 + 8 - 3 = 26

22/2 + 32/8 + 6 + 8 - 3 = 26

11 + 4 + 6 + 8 - 3 = 26

15 + 6 + 8 - 3 = 26

21 + 8 - 3 = 26

29 - 3 = 26

26 = 26

(7x-22)/2+(x+6)/4 + x + x+1 = 26

(7(6)-22)/2 + (6+6)/4 + 6 + 6+1 = 26

(42-22)/2 + 12/4 + 6 + 6 + 1 = 26

20/2 + 12/4 + 6 + 6 + 1 = 26

10 + 3 + 6 + 6 + 1 = 26

13 + 6 + 6 + 1 = 26

19 + 6 + 1 = 26

25 + 1 = 26

26 = 26

Espero te sirva de ayuda.