Question

Alguien que me ayude

Answer 1

Respuesta:

3/10,    1/36,   2/3,   -9$\sqrt{3}$i

Explicación paso a paso:

a) $\sqrt[3]{\frac{3^{3} }{2^{3} 5^{3} } }$ = $\frac{3}{10}$

b) $(\frac{1}{6}) ^{36.\frac{1}{3}.\frac{1}{3}.\frac{1}{2} }$   = $(\frac{1}{6}) ^{2 }$ = 1/36

c) $(\frac{2^{2}}{3^{2} }) ^{6.\frac{1}{3}.\frac{1}{2}.\frac{1}{2} }$   = $(\frac{2}{3}) ^{2.6.\frac{1}{3}.\frac{1}{2}.\frac{1}{2} }$   = $\frac{2}{3}$

d) $\frac{\sqrt{ -10 -17}}{\frac{2-6}{12}}$   = $\frac{\sqrt{ -27}}{\frac{-4}{12}}$  = $\frac{3\sqrt{ -3}}{\frac{-1}{3}}$   = -9$\sqrt{3}$i