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Respuestas a la pregunta
Respuesta:
Lado AB = 4 , Lado BC = 3 y Lado AC = 2
Lado AB = a , Lado BC = b , Lado AC = c
Cos(A) = ( ((a)²-(b)²-(c)²)/(-2bc) ) ; a = 4 , b = 3 y c = 2
Cos(A = ( ((4)²-(3)²-(2)²)/(-2×3×2) )
Cos(A) = ( ( 16-9-4 )/( -12 ))
Cos(A) = (( 7-4 )/(-12))
Cos(A) = 3/-12
Cos(A) = (3÷3)/(-12÷3)
Cos(A) = 1/-4
Cos(A) = - 1/4
A = arccos( - 1/4 )7
A ≈ 104,48°
(a)/Sen(A) = (b)/Sen(B) , a = 4 , A ≈ 104,48° y b = 3
4/Sen(104,48°) = 3/Sen(B) ; Sen(104,48°) ≈ 0,97
4/0,97 = 3/Sen(B) ; 4/0,97 ≈ 4,12
4,12 = 3/Sen(B)
Sen(B) = 3/4,12 ; 3/4,12 ≈ 0,73
Sen(B) ≈ 0,73
B = arcsen(0,73)
B ≈ 46,89°
A+B+C = 180° ; A = 104,48° y B = 46,89°
(104,48°)+(46,89°)+C = 180°
151,37°+C = 180°
C = 180°-151,37°
C = 28,63°
C+w+w = 180° ; C = 28,63°
(28,63°)+2w = 180°
2w = (180-28,63)°
2w = 151,37°
ñ1 (2/2)w = 151,37°/2
w = 75,685°
A+H = 180° ; A = 104,48°
(104,48°)+H = 180°
H = (180-104,48)°
H = 75,52°
w+H+D = 180° ; w = 75,685° y H° = 75,52°
75,52°+75,685° = 180°
(75,52+75,685)° = 180°
151,205°+D = 180°
D = 180°-151,205°
D = 28,795°
BC/Sen(D) = CD/Sen(w) ; BC = 3 , D = 28,795° y w = 75,685°
3/Sen(28,795°) = CD/Sen(75,685°) ; Sen(28,795°) ≈ 0,48
3/0,48 = CD/Sen(75,685°) ; Sen(75,685°) ≈ 0,97
3/0,48 = CD/0,97
3×0,97 = 0,48CD
2,91 = 0,48CD
2,91/0,48 = CD
CD = 2,91/0,48 ; 2,91/0,48 = 6,062
CD = 6,0625
AD = AC+CD ; AC = 2 y CD = 6,0625
AD = 2+6,0625
AD = 8,0625 ==== > 8,0625 ≈ 8 entonces la respuesta correcta es la alternativa d ) 8