Matemáticas, pregunta formulada por Scarjr01, hace 14 días

alguien porfavor ayudeeenmeee, es para hoy 25

Adjuntos:

Respuestas a la pregunta

Contestado por darwinstevenva
1

Respuesta:

Lado AB = 4 , Lado BC = 3 y Lado AC = 2

Lado AB = a , Lado BC = b , Lado AC = c

Cos(A) = ( ((a)²-(b)²-(c)²)/(-2bc) ) ; a = 4 , b = 3 y c = 2

Cos(A = ( ((4)²-(3)²-(2)²)/(-2×3×2) )

Cos(A) = ( ( 16-9-4 )/( -12 ))

Cos(A) = (( 7-4 )/(-12))

Cos(A) = 3/-12

Cos(A) = (3÷3)/(-12÷3)

Cos(A) = 1/-4

Cos(A) = - 1/4

A = arccos( - 1/4 )7

A ≈ 104,48°

(a)/Sen(A) = (b)/Sen(B) , a = 4 , A ≈ 104,48° y b = 3

4/Sen(104,48°) = 3/Sen(B) ; Sen(104,48°) ≈ 0,97

4/0,97 = 3/Sen(B) ; 4/0,97 ≈ 4,12

4,12 = 3/Sen(B)

Sen(B) = 3/4,12 ; 3/4,12 ≈ 0,73

Sen(B) ≈ 0,73

B = arcsen(0,73)

B ≈ 46,89°

A+B+C = 180° ; A = 104,48° y B = 46,89°

(104,48°)+(46,89°)+C = 180°

151,37°+C = 180°

C = 180°-151,37°

C = 28,63°

C+w+w = 180° ; C = 28,63°

(28,63°)+2w = 180°

2w = (180-28,63)°

2w = 151,37°

ñ1 (2/2)w = 151,37°/2

w = 75,685°

A+H = 180° ; A = 104,48°

(104,48°)+H = 180°

H = (180-104,48)°

H = 75,52°

w+H+D = 180° ; w = 75,685° y H° = 75,52°

75,52°+75,685° = 180°

(75,52+75,685)° = 180°

151,205°+D = 180°

D = 180°-151,205°

D = 28,795°

BC/Sen(D) = CD/Sen(w) ; BC = 3 , D = 28,795° y w = 75,685°

3/Sen(28,795°) = CD/Sen(75,685°) ; Sen(28,795°) ≈ 0,48

3/0,48 = CD/Sen(75,685°) ; Sen(75,685°) ≈ 0,97

3/0,48 = CD/0,97

3×0,97 = 0,48CD

2,91 = 0,48CD

2,91/0,48 = CD

CD = 2,91/0,48 ; 2,91/0,48 = 6,062

CD = 6,0625

AD = AC+CD ; AC = 2 y CD = 6,0625

AD = 2+6,0625

AD = 8,0625 ==== > 8,0625 ≈ 8 entonces la respuesta correcta es la alternativa d ) 8

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