Question

Alguien me puede ayudar porfa

Answer 1

Respuesta:

no lo pude resolver amiga perdón amigo

Answer 2

Respuesta:

a)1154

Explicación paso a paso:

si

$(x^{2})^{4}=((x^{2})^{2})^{2}$

$(\sqrt{2} +1)^{2} =3+2\sqrt{2}$

$(3+2\sqrt{2})^{2}= 17+12\sqrt{2}$

$(17+12\sqrt{2} )^{2} =577+408\sqrt{2}$

si

$(y^{2})^{4}=((y^{2})^{2})^{2}$

$(\sqrt{2} -1)^{2} =3-2\sqrt{2}$

$(3-2\sqrt{2})^{2}= 17-12\sqrt{2}$

$(17-12\sqrt{2} )^{2} =577-408\sqrt{2}$

$P=577+408\sqrt{2}+577-408\sqrt{2}=1154$