Question

alguien me puede ayudar con estos dos problemas por favorr

Answer 1

$Hola! \\ \\ \boxed{6} \\ \\ en~la~figura~ [\alpha = \beta ]~-\ \textgreater \ \begin{cases} \alpha =3x+10 \\ \beta =5x-50\end{cases} \\ \\ entonces~igualamos~observe: \\ 3x+10=5x-50 \\ \\ -2x=-60 \\ \\ \boxed{x=30} \\ \\ =\ \textgreater \ \begin{cases} \alpha =3(30)+10 \\ \boxed{\alpha =100\°} \\ \\ \beta =5(30)-50 \\ \boxed{ \beta =100\°} \\ \\ E+ \beta =180 \\ E+100=180 \\ \boxed{E=80}\end{cases}$

$====================================== \\ \boxed{7} \\ \\ La~soma~de~los~a'ngulos~internos~es~180\°, entonces~calculemos~''c'' \\ \\ \^a+\^b+\^c=180~~~--\ \textgreater \ se~sabe~que: ~\begin{cases}\^a=47\° 31' \\ \^b=78\°56'\end{cases} \\ \\ reemplazando: \\ \\ \underbrace{47\°31'+78\°56'}_{126\°42'}+c=180 \\ \\ 126\°42'+\^c=180\°~~~--\ \textgreater \ que~[180\°=179\°60' \\ \\ \^c=\underbrace{179\°60'-126\°42'}_{53\°17'} \\ \\ \boxed{\^c=53\°17'} \\ \\ Bueno~eso~es~todo~suerte!$