Question

alguien me puede ayudar

Answer 1

EN EL TRIÁNGULO PQR :
5X + 2X + 2X = 180 °
DESPEJANDO X:
9X - 180° ------> X = 180°/9 = 20°
∡ P = 5X  = 5.20° = 100°
∡ Q = 2X = 2.20° = 40°
∡ R = 2X = 2.20° = 40°

EN EL TRIÁNGULO DEF:
2X+5 + X+5 + 2X+10 = 180°
DESPEJANDO X:
5X + 20 = 180°
5X = 180° - 20 
X= (180° - 20 ) 5 = 160° / 5 = 32°
∡ D = 2 . 32° + 5 = 69°
∡ E = 32° + 5 = 37°
∡ F = 2 . 32° + 10 = 64° + 10 = 74°