Question

alguien me ayuda, xfaa​

Answer 1

RESOLVER:

a) $\frac{5}{12}-\frac{4}{3}\div \left(\frac{4}{3}+2\right)+\left(-\frac{3}{5}\right)$

$\left(\frac{4}{3}+2\right):\frac{10}{3}$

$=\frac{5}{12}-\frac{4}{3}\div \frac{10}{3}+\left(-\frac{3}{5}\right)$

$\frac{4}{3}\div \frac{10}{3}:\frac{2}{5}$

$=\frac{5}{12}-\frac{2}{5}+\left(-\frac{3}{5}\right)$

$\frac{5}{12}-\frac{2}{5}+\left(-\frac{3}{5}\right):-\frac{7}{12}$

$=-\frac{7}{12}$

b) $\left[\frac{6}{5}\div \frac{9}{10}-\left(2\cdot \frac{7}{12}\right)\right]+\frac{7}{24}$

$\left[\frac{6}{5}\div \frac{9}{10}-\left(2\cdot \frac{7}{12}\right)\right]:\frac{1}{6}$

$=\frac{1}{6}+\frac{7}{24}$

$\frac{1}{6}+\frac{7}{24}:\frac{11}{24}$

$=\frac{11}{24}$

c) $\frac{5}{6}-\left(\frac{3}{2}\cdot \frac{2}{6}\right)+\left(\frac{1}{5}\div \left(-\frac{2}{10}\right)\right)$

$\frac{2}{6}:\frac{1}{3}$

$=\frac{5}{6}-\left(\frac{3}{2}\cdot \frac{1}{3}\right)+\left(\frac{1}{5}\div \left(-\frac{2}{10}\right)\right)$

$\frac{2}{10}:\frac{1}{5}$

$=\frac{5}{6}-\left(\frac{3}{2}\cdot \frac{1}{3}\right)+\left(\frac{1}{5}\div \left(-\frac{1}{5}\right)\right)$

$\left(\frac{3}{2}\cdot \frac{1}{3}\right):\frac{1}{2}$

$=\frac{5}{6}-\frac{1}{2}+\left(\frac{1}{5}\div \left(-\frac{1}{5}\right)\right)$

$\left(\frac{1}{5}\div \left(-\frac{1}{5}\right)\right):-1$

$=\frac{5}{6}-\frac{1}{2}-1$

$=-\frac{2}{3}$

d) $2+\left(\frac{2}{3}\cdot \:0.18+2.9\right)$

$=2+\frac{2}{3}\cdot \:0.18+2.9$

$=0.18\cdot \frac{2}{3}+4.9$

$=0.12+4.9$

$=5.02$

$Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)$