Question

alguien me ayuda sacandole area y perimetro porfavor​

Answer 1

Respuesta:

$h = \sqrt{4^{2} + 6^{2}} \\ h = \sqrt{52} \\ h =7.211\\\\Perimetro\\p = 5 + 5 + 8 + 8 + 4 + 6 + 7.211\\p = 43.211\\\\Area del Rectangulo\\A_{r} = b*h\\A_{r} =5 * 12\\A_{r} = 60\\\\\\Area del Triangulo\\A_{t} = \frac{b*h}{2}\\A_{t} =\frac{4*6}{2}\\A_{t} =12\\\\\\Area TotalA = A_{r} +A_{t}\\A = 60 + 12\\A = 72$