Question

Alguien me ayuda con esto? lo agradeceria, doy corona

Answer 1

Respuesta:

-1

Explicación paso a paso:

$Se\ sabe\ que:\\\boxed {tanA+tanB=\frac{tanA+tanB}{1-tanAtanB}}\\\\Entonces,\ sea:\\A=3\alpha-2\theta\\B=3\theta-2\alpha\\Reeplazamos:\\tan(3\alpha-2\theta+3\theta-2\alpha)=\frac{tan(3\alpha-2\theta)+tan(3\theta-2\alpha)}{1-tan(3\alpha-2\theta)tan(3\theta-2\alpha)} \\\\tan(\alpha+\theta)=\frac{2+3}{1-2\times 3} \\\\tan(\alpha+\theta)=\frac{5}{1-6}\\\\tan(\alpha+\theta)=\frac{5}{-5}\\\\tan(\alpha+\theta)=-1$