Question

Algebra-ecuaciones de 2do grado ​

Answer 1

Respuesta:

x = 3

Explicación paso a paso:

(x+4)/(x+4) + (x-4)/(x+4) = -50/7

((x+4)^2 + (x-4)^2) / (x-4)(x+4)  = -50/7

(x^2 + 8x + 16 + x^2 - 8x + 16) / x^2 - 16  = -50/7

2x^2  + 32  / x^2 - 16 = -50/7

2 (x^2 + 16) / x^2 - 16 = -50 / 7

x^2 + 16 / x^2 - 16 = -25 / 7

7 (x^2 + 16) = -25 (x^2 -16)

7x^2 + 112 = -25 x^2 + 400

7x^2  +  25x^2 = 400 - 112

32x^2 = 288

x^2 = 9

x = 3

Answer 2

Respuesta:

Lit D

Explicación paso a paso:

Un gusto ayudarte :)

$\frac{x+4}{x-4}+\frac{x-4}{x+4}=-\frac{50}{7}\\\\\frac{x+4}{x-4}+\frac{x-4}{x+4}=-\frac{50}{7}=>\frac{7(x+4)^{2}+7(x-4)^{2} =-50\left(x-4\right)\left(x+4\right)}{7\left(x-4\right)\left(x+4\right)} \\\\7\left(x+4\right)^2+7\left(x-4\right)^2=-50\left(x-4\right)\left(x+4\right)\\\\7\left(x^2+8x+16\right)+7\left(x^2-8x+16\right)=-50\left(x^2-16\right)\\\\7x^2+56x+112+7x^2-56x+112=50\left(x^2-16\right)\\\\7x^2+7x^2+56x-56x+112+112=50\left(x^2-16\right)$

$\\14x^2+112+112=-50x^2+800\\\\14x^2+224=-50x^2+800\\\\14x^2=-50x^2+800-224\\\\14x^2+50x^2=576\\\\64x^2=576\\\\\frac{64x^2}{64}=\frac{576}{64}\\\\x^2=9\\\\\sqrt{x^{2} } =\pm \sqrt{9} \\\\x =\pm3\\\\x_{1} =+3\\\\x_{2} =-3$