Question

álgebra de matrices ​

Answer 1

Solucion:

$2A = 2\left[\begin{array}{ccc}1&-1&1\\2&2&1\\0&-4&1\end{array}\right] =\left[\begin{array}{ccc}2&-2&2\\4&4&2\\0&-8&2\end{array}\right]\\\\\\\\3B = 3\left[\begin{array}{ccc}2&0&5\\0&4&0\\3&0&7\end{array}\right] = \left[\begin{array}{ccc}6&0&15\\0&12&0\\9&0&21\end{array}\right]$

Remplazamos:

$C = 2A - 3B = \left[\begin{array}{ccc}2&-2&2\\4&4&2\\0&-8&2\end{array}\right] -\left[\begin{array}{ccc}6&0&15\\0&12&0\\9&0&21\end{array}\right]\\\\\\C = \left[\begin{array}{ccc}-4&-2&-13\\4&-8&2\\-9&-8&-19\end{array}\right]$