Question

álgebra de baldor ejercicio 63 de 1 al 12
Porfavor es URGENTE ​

Answer 1

Respuesta:

1.      $(a-3)^{2} = a^{2}-2(a)(3)+3^{2} = a^{2}-6a+9$

2.     $(x-7)^{2} = x^{2} -2(x)(7)+7^{2} = x^{2} -14x+49$

3.     $(9-a)^{2} = 9^{2}-2(9)(a)+a^{2} = 81-18a+a^{2}$

4.     $(2a-3b)^{2} = (2a)^{2}-2(2a)(3b)+(3b)^{2} = 4a^{2}-12ab+9^{2}$

5.     $(4ax-1)^{2} = (4ax)^{2}-2(4ax)(1)+1^{2} = 16a^{2}x^{2}-8ax+1$

6.     $(a^{3}-b^{3} )^{2} = (a^{3} )^{2}-2(a^{3})(b^{3} )+(b^{3}) ^{2} = a^{6}-2a^{3} b^{3}+b^{6}$

7.      $(3a^{4}-5b^{2})^{2} = (3a^{4} )^{2}-2(3a^{4} )(5b^{2} )+(5b^{2} )^{2} = 9a^{8}-30a^{4} b^{2}+25b^{4}$

8.      $(x^{2} -1)^{2} = (x^{2} )^{2}-2x^{2}*1+1^{2} = x^{4}-2x^{2} +1$

9.      $(x^{5}-3ay^{2} )^{2} = (x^{5} )^{2}-2x^{5}*3ay^{2} +(3ay^{2})^{2} = x^{10}-6ax^{5}y^{2}+9a^{2}y^{4}$

10.     $(a^{7} -b^{7} )^{2} = (a^{7} )^{2}-2a^{7}b^{7}+(b^{7} )^{2} = a^{14}-2a^{7} b^{7} +b^{14}$

11.      $(2m-3n)^{2} = (2m)^{2}-2(2m)(3n)+(3n)^{2} = 4m^{2}-12mn+8n^{2}$

12.     $(10x^{3}-9xy^{5})^{2} = (10x^{3} )^{2}-2*10x^{3}*9xy^{5}+(9xy^{5} )^{2} = 100x^{6}-180x^{4} y^{5}+81x^{2}y^{10}$

Explicación:

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