Question

algebra baldor 0,4x^2y+31+(3)/(8)xy^2-0,6y^3-(2)/(5)x^2y-0,2xy^2+(1)/(4)y^3-6

Answer 1

Respuesta:

Solución:

0.4x^2y+31+\frac{3}{8}xy^2-0.6y^3-\frac{2}{5}x^2y-0.2xy^2+\frac{1}{4}y^3-6=-0.35y^3+0.175xy^2+25

Explicación paso a paso: