Question

Ahmet and Avril are playing in a seesaw. Ahmet weighs 78 Lbs. and Avril weighs 65 Lbs. If Avril is seated 5 ft from the center of balance, how far is Ahmet seated from the center?
-14.17 ft
-4.17 ft
-4.70 ft

Answer 1

Respuesta:

For a balanced seesaw, we have the following proportion:

r1/r2 = W2/W1

r1 = distance Jo is seated from center

W1 = Jo's weight = 65 lb

r2 = distance Tim is seated from center = 6 ft

W2 = Tim's weight = 78 lb

Plug in the numbers and solve for r1.

Explicación paso a paso: