Question

ahí denme porfavor les doy 5 estrellas ​

Answer 1

Respuesta:

Aplica propiedades de la potenciacion

1.

$\left(-3\right)^2\left(-3\right)^3\left(-3\right)^4\\\\\:a^c=a^{b+c}\\\\=\left(-3\right)^{2+3+4}\\\\\\=-3^9\\\\=-19683$

2.

$\left(x^3\right)^2.\left(x^4\right)^3\\\\\left(x^3\right)^2\left(x^4\right)^3\\\\=x^6\left(x^4\right)^3\\\\=x^6x^{12}\\\\=x^{6+12}\\\\=x^{18}$

3.

$\frac{\left(-6\right)^9}{\left(-6\right)^3}\\\\=\left(-6\right)^{9-3}\\\\=\left(-6\right)^6\\\\=6^6\\\\=46656$

4.

$\frac{5^6\cdot \:5^4\cdot \:5^8}{5^2\cdot \:5}\\\\=\frac{5^4\cdot \:5^4\cdot \:5^8}{5}\\\\=5^3\cdot \:5^4\cdot \:5^8\\\\=5^{15}$

Simplificar:

1.

$\frac{a^7b^4}{a^4b^3}\\\\=\frac{a^3b^4}{b^3}\\\\=a^3b$

2.

$\frac{3^8a^5b^4c^7}{3^6b^3a^4c^5}\\\\=\frac{3^2a^5b^4c^7}{b^3a^4c^5}\\\\=\frac{3^2ab^4c^7}{b^3c^5}\\\\=3^2abc^2\\\\3^2=9\\\\=9abc^2$

Answer 2

Respuesta:

2. a)$(-3)^{9}$ b) $x^{18}$ c) $(-6)^{6}$      3. a) $a^{3} b$  b) $9abc^{2}$

Explicación paso a paso:

2.

a) $(-3)^{2+3+4\\}$ = $(-3)^{9}$

b)  $x^{6}$. $x^{12}$= $x^{18}$

c) $(-6)^{9-3}$ =$(-6)^{6}$

d) $5^{(6+4+8-(2+1)}$ = $5^{(18-3)}$ = $5^{15}$

3.

a) $a^{(7-4)} b^{(4-3)}$ = $a^{3} b^{1}$

b) $3^{(8-6)} a^{(5-4)} b^{(4-3)} c^{(7-5)}$ = $3^{2} a^{1} b^{1} c^{2}$ = $9abc^{2}$