Question

a)(x4+4x3-2x2-x-38)÷(x-2)​

Answer 1

Respuesta:

$\left(x4+4x3-2x2-x-38\right)\div \left(x-2\right)​\\x\cdot \:4+4x\cdot \:3-2x\cdot \:2-x-38\\=3x+4\cdot \:3x-2\cdot \:2x-38\\=3x+12x-2\cdot \:2x-38\\=3x+12x-4x-38\\=11x-38\\x = 11 - 38\\x = -27$

Explicación paso a paso: