Question

a.
$- \sqrt[3]{4} \times \sqrt[3]{6}$
b.
$\sqrt[3]{4 }$
c.
$( \sqrt[3]{2 {}^3{} }$
d.
$( \sqrt[6]{2 {}^3{} }$
​

Answer 1

$-\sqrt[3]{4} .\sqrt[3]{6}\\\\-\sqrt[3]{24} \\\\-\sqrt[3]{2^{3}.3 }\\\\-2\sqrt[3]{3}$

Eternamente axllxa