Question

A=$\sqrt[12]{3^{3} } -5^{2} -2^{1} +\sqrt[3]{3^{2} } -3^{2} + 8$

Answer 1

Explicación paso a paso:

$A=\sqrt[12]{3^{3} } -5^{2} -2^{1} +\sqrt[3]{3^{2} } -3^{2} +8$

$a = \sqrt[12]{ {3}^{3} } - 25 - 2 + \sqrt[3]{ {3}^{2} } - 9 + 8$

$a = \sqrt[12]{ {3}^{3} } -28 + \sqrt[3]{ {3}^{2} }$

$a = {3}^{ \frac{3}{12} } - 28 + {3}^{ \frac{2}{3} }$

$a = {3}^{ \frac{1}{4} } + {3}^{ \frac{2}{3} } - 28$

$a = {3}^{ \frac{1}{4} \times \frac{2}{3} } - {3}^{3} - 1$

$a = {3}^{ \frac{1}{6} \div \frac{3}{1} } - 1$

$a = {3}^{ \frac{1}{2} } - 1$

$a = \sqrt[2]{3} - 1$