Question

A rectangular house has a perimeter of 40 metres and the length is 4 metres more than the width. What are the dimensions of the house?

Answer 1

Respuesta:

P = 40 m

L = x + 4

W = x

P = (2 L) (2 w)

Equation

$2(x + 4) + 2x = 40 \\ 2x + 8 + 2x = 40 \\ 4x + 8 = 40 \\ 4x = 40 - 8 \\ 4x = 32 \\ x = \frac{32}{4} \\ x = 8$

Length:

x + 4 = 12 m

Width:

x = 8 m

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