Question

a quién responda bien le doy corona. Resolver:
> $(\frac{2}{3})^{3}$
>$(\frac{2}{5}) ^{4}$
>$(-\frac{3}{2}) ^{3}$
>$(\frac{7}{2})^{-3}$

Answer 1

Respuesta:

HOLA!!!

Tema: Potenciación.

Resolvemos

$( \frac{2}{3} ) {}^{3} = \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} = \frac{2 \times 2 \times 2}{3 \times 3 \times 3} = \frac{8}{27}$

$( \frac{2}{5}) {}^{4} = \frac{2}{5} \times \frac{2}{5 } \times \frac{2}{5} \times \frac{2}{5} = \frac{2 \times 2 \times 2 \times 2}{5 \times 5 \times 5 \times 5} = \frac{16}{625}$

$( - \frac{3}{2} ) {}^{3} = \frac{3}{2} \times \frac{3}{2} \times \frac{3}{2} = \frac{3 \times 3 \times 3}{2 \times 2 \times 2} = - \frac{27}{8}$

$( \frac{7}{2} ) {}^{ - 3} =( \frac{2}{7} ) {}^{3} = \frac{2}{7} \times \frac{2}{7} \times \frac{2}{7} = \frac{2 \times 2 \times 2}{7 \times 7 \times 7} = \frac{8}{343}$

Espero haberte ayudado.