Question

A) P1 (-5, 3) P2 (4 -6)

B) P1 (2, 3) P2 (-4,5)

C) P1 (1,7) P2 (1,-5)

D) P1 (0,7) P2 (-5, -4)​

Answer 1

Respuesta:

$A.) \: P1 = ( - 5;3) \: P2 = (4; - 6) \\ d = \sqrt{(x2 - x1 {)}^{2} + (y2 - y1 {)}^{2} } \\ d = \sqrt{(4 - ( - 5) {)}^{2} + ( - 6 - 3 {)}^{2} } \\ d = \sqrt{( 4 + 5 {)}^{2} + ( - 9 {)}^{2} } \\ d = \sqrt{(9 {)}^{2} + ( - 9 {)}^{2} } \\ d = \sqrt{81 + 81} \\ d = \sqrt{162} \\ d = 12.68 \\ B.) \: P1 = (2 ;3) \: P2 = ( - 4 ;5) \\ d = \sqrt{(x2 - x1 {)}^{2} + (y2 - y1 {)}^{2} } \\ d = \sqrt{( - 4 - 2 {)}^{2} + (5 - 3 {)}^{2} } \\ d = \sqrt{( - 6 {)}^{2} + (2 {)}^{2} } \\ d = \sqrt{36 + 4} \\ d = \sqrt{40} \\ d = 6.32 \\ C.) \: P1 = (1 ;7) \: P2 = (1 ;5) \\ d = \sqrt{(x2 - x1 {)}^{2} + (y2 - y1 {)}^{2} } \\ d = \sqrt{(1 - 1 {)}^{2} + ( - 5 - 7 {)}^{2} } \\ d = \sqrt{(0 {)}^{2} + ( - 12 {)}^{2} } \\ d = \sqrt{144} \\ d = 12 \\ D.) \: P 1 = (0;7) \: P2 = ( - 5 ; - 4) \\ d = \sqrt{(x2 - x1 {)}^{2} + (y2 - y1 {)}^{2} } \\ d = \sqrt{( - 5 - 0 {)}^{2} + ( - 4 - 7 {)}^{2} } \\ d = \sqrt{( - 5 {)}^{2} + ( - 11 {)}^{2} } \\ d = \sqrt{25 + 121} \\ d = \sqrt{146} \\ d = 12.08$

Explicación paso a paso:

La "d" significa Distancia

Espero que te sirva

Si es así

#CORONA_POR_FAVOR

Answer 2

Respuesta:

a

Explicación paso a paso: