A number has two digits. If these two digits are multiplied, their product is equal to half the original number.
What was the original number?
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Answer:
To solve this problem we must realize a system to represent our problem, we have:
ab = 2 · a · b
We decompose the number ab, we have:
(10 · a) + b = 2 · a · b
10 · a = 2 · a · b - b
We take common factor b, we have:
10 · a = b · (2a-1)
Decompose the number 10:
5 · 2 · a = b · (2a-1)
We perform coefficient equalization between 5 and 2a-1 because this equality is met, the two will always be odd:
5 = 2a-1
a = 3
Then b = 6
The number is 36, the multiplication of your digits is 18 and this is your half.
To solve this problem we must realize a system to represent our problem, we have:
ab = 2 · a · b
We decompose the number ab, we have:
(10 · a) + b = 2 · a · b
10 · a = 2 · a · b - b
We take common factor b, we have:
10 · a = b · (2a-1)
Decompose the number 10:
5 · 2 · a = b · (2a-1)
We perform coefficient equalization between 5 and 2a-1 because this equality is met, the two will always be odd:
5 = 2a-1
a = 3
Then b = 6
The number is 36, the multiplication of your digits is 18 and this is your half.
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