Question

A * B = a3 + b3 + 3ab (a+b) Hallar (2 * 0) * (0 * 1) A)513 B)730 C)729 D)19 E)512

Answer 1

A * B = a³ + b³ + 3ab(a + b)

(2 * 0) = a³ + b³ + 3ab(a + b) = 8 + 0 + 0 = 8
a = 2
b = 0

(0 * 1) = a³ + b³ + 3ab(a + b) = 0 + 1 + 0 = 1
a = 0
b = 1

Hallar:
(2 * 0) * (0 * 1)
8 * 1

8 * 1 = a³ + b³ + 3ab(a + b) = 512 + 1 + 216 = 729
a = 8
b = 1