Question

a) 5[2x-4(3x+1)]= -10x+20
b) X-13=4[3x-4(x-2)]
c) 2x+3(x-3)=6[2x-3(x-5)]
d) X+4[3-2(x-1)]=5[x-3(2x-4)]+1

Answer 1

Respuesta:

a)

$5[2x-4(3x+1)]= -10x+20\\5[2x-12x-4]= -10x+20\\10x-60x-20= -10x+20\\-50x= -10x+40\\-40x = 40\\x = -1$

b)

$x-13=4[3x-4(x-2)]\\x-13=4[3x-4x+8]\\x-13=4[-x+8]\\x-13=-4x+32\\5x = 45\\x = 9$

c)

$2x+3(x-3)=6[2x-3(x-5)]\\2x+3x-9=6[2x-3x+15]\\5x-9=12x-18x+90\\5x=-6x+99\\11x = 99\\x = 9$

d)

$x+4[3-2(x-1)]=5[x-3(2x-4)]+1\\x+4[3-2x+2]=5[x-6x+12]+1\\x+4[5-2x]=5[-5x+12]+1\\x+20-8x=-25x+60+1\\20-7x = -25x + 61\\18x = 41\\x = \frac{41}{18}$