Question

a)(3²)⁰-9+(8¹.8²)-49+(7.4)=
b)48+(36:3)+(4²)⁴-3³.3⁰=
c)(5³)²+(9⁵:9³)-(2².2³.2¹)=​

Answer 1

$a) \: {( {3}^{2} )}^{0} - 9 + ( {8}^{1} . {8}^{2} ) - 49 + (7.4)$

$1 - 9 + 512 - 49 + 28$

$\boxed{483}$

$b) \: 48 + (36 \div 3) + { ({4}^{2}) }^{4} - {3}^{3} . {3}^{0}$

$48 + 12 + 65536 - 27$

$\boxed{65569}$

$c) \: {( {5}^{3}) }^{2} + ( {9}^{5} \div {9}^{3} ) - ( {2}^{2} . {2}^{3} . {2}^{1} )$

$15625 + 81 - 64$

$\boxed{15642}$