Matemáticas, pregunta formulada por sandrapatricia45, hace 24 días

A. (-(3+2)+(-4)-(-1)+(-(-4+1).
B. 8-(-3+(8-7)-(6+1)+(5-7)+5)​

Respuestas a la pregunta

Contestado por Usuario anónimo
1

RESOLVER:

a) -\left(3+2\right)+\left(-4\right)-\left(-1\right)+\left(-\left(-4+1\right)\right)

Resolvemos la expresión \left(3+2\right)=5

=-5+\left(-4\right)-\left(-1\right)+\left(-\left(-4+1\right)\right)

Ahora resolvemos la expresión dentro paréntesis \left(-\left(-4+1\right)\right)

-\left(-4+1\right)\\\\\left(-4+1\right)=-3\\\\=-\left(-3\right)\\\\=3

=-5+\left(-4\right)-\left(-1\right)+3

Operamos:

-5+\left(-4\right)-\left(-1\right)+3\\\\+\left(-4\right)=-4\\\\=-5-4-\left(-1\right)+3\\\\-5-4=-9\\\\=-9-\left(-1\right)+3\\\\-\left(-1\right)=+1\\\\=-9+1+3\\\\=-8+3\\\\-8+3=-5\\\\\boxed{=-5}

b) 8-\left(-3+\left(8-7\right)-\left(6+1\right)+\left(5-7\right)+5\right)

-3+\left(8-7\right)-\left(6+1\right)+\left(5-7\right)+5\\\\\left(8-7\right)=1\\\\=-3+1-\left(6+1\right)+\left(5-7\right)+5\\\\\left(6+1\right)=7\\\\=-3+1-7+\left(5-7\right)+5\\\\\left(5-7\right)=-2\\\\=-3+1-7-2+5\\\\=-6\\\\=8-\left(-6\right)\\\\\boxed{=14}

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