Question

a) 2(2x - 3) = 6 + x
b) $\frac{3}{4}$ (2y - 4) = y + 19
c) 4(x - 10) = -6(2 - x) - 6x

Answer 1

a) 2(2x-3)=6+x
4x-6= 6+x
4x-x= 6+6
3x= 12
x= 12/3
x=4

b)
$\frac{3}{4} (2y - 4) = y + 19 \\ \frac{6y}{4} - 3 = y + 19 \\ \frac{6y - 3(4)}{4} = \frac{(4)y + 19(4)}{4} \\ \frac{6y - 12}{4} = \frac{4y + 76}{4}$
$6y - 12 = 4y + 76 \\ 6y - 4y = 12 + 76 \\ 2y = 88 \\ y = \frac{88}{2} \\ y = 44$
c) 4(x-10)= -6(2-x) -6x
4x-40= -12+6x-6x
4x= -12+40
4x= 28
x= 28/4
x= 7