Question

a). 2(2×-5)=3(×-1)-4

b). 3 ( z - 2)+ 10 = 2(2 z+ 2 )+2

c). 3× + 6 (× +1) = 3 (×+ 1) +5

ayuda pues xde ​

Answer 1

a). 2(2×-5)=3(×-1)-4

R//

x = 3

Solución :

4x - 10 = 3 (x - 1 ) - 4

4 - 10 = 3x - 3 - 4

4x - 10 = 3x - 7

4x - 10 - 3x = -7

4x - 3x = -7 + 10

x = - 7 + 10

x = 3

b). 3 ( z - 2)+ 10 = 2(2 z+ 2 )+2

R//

z = 2/3

Solución :

z -2 + 10 = 2 (2 z + 2) + 2

z - 2 + 10 = 4z + 4 + 2

2 + 8 = 4z + 4 + 2

2 + 8 = 4z = 6

2 + 8 - 4z = 6

z - 4z = 6 - 8

- 3z = 6 - 8

- 3z = - 2

z = 2/3

c). 3× + 6 (× +1) = 3 (×+ 1) +5

R//

x = 1/3

Solución :

3x + 6x + 6 = 3 (x + 1) + 5

3x + 6x + 6 = 3x + 3 + 5

6x + 6 = 3 + 5

6x + 6 = 8

6x = 8 - 6

6x = 2

x = 1/3

Explicación paso a paso :

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Answer 2

a)

$x = 3$

B)

$z = \frac{2}{3}$

C)

$x = \frac{1}{3}$

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