Question

a\ ( √16+2⁵:2⁵).2⁰-√25
b\ ( ³√125-10:2+9⁰).√2.(31+41)
c\ (10⁸:10⁶).3+5.⁴√16-10²:10
d\ (3²+5²):2+(3-2:√4).√100
porfa ayúdenme con esos cálculos o expliquenme , es para aprobar la materia URGENTE ​

Answer 1

$(\sqrt{16} +\frac{2^{5} }{2^{5} } ). 2^{0} - \sqrt{25} = ( 4 + 1 ). 1 - 5 = (5).1-5 = 5 - 5 = 0$

$(\sqrt[3]{125} -\frac{10}{2} + 9^{0} ). \sqrt{2} .(31+41) = (5 - 5 + 1) . \sqrt{2} .(72) = (1) . \sqrt{144} = \sqrt{144} =12$

$(10^{8} : 10^{6}). 3+5 .\sqrt[4]{16} - \frac{10^{2} }{10} = (10^{2}).3+5.2-10 = (100).3+10-10=300+10-10=300$

$\frac{(3^{2} +5^{2} )}{2} + \frac{(3-2)}{\sqrt{4} } .\sqrt{100} = \frac{(9+25)}{2} +\frac{(1)}{2} .10 = \frac{34}{2} + \frac{10}{2} = 17 +5=22$