Question

(a+1)(a+2)
(x+2)(x+4)
(x+5)(x-2)
(m-6)(m-5)
(x-3)(x-1)
(n-19)(n+10) ​

Answer 1

$\bf \textcolor {blue}{respuesta \: abajo = }$

(a+1)(a+2) = a²+3a+2

a²+2a+a+2=

a²+3a+2

(x+2)(x+4) = ײ+6×+8

ײ+4×+2×+8=

ײ+6×+8

(x+5)(x-2) = ײ+3×-10

ײ-2×+5×-10=

ײ+3×-10

(m-6)(m-5) = m²-11m+30

m²-5m-6m+30

m²-11m+30

(x-3)(x-1) = ײ-4×+3

ײ-×-3×+3=

ײ-4×+3

(n-19)(n+10) = n²-9n-190

n²+10n-19n-190=

n²-9n-190

Lasers✨