Question

A=(1/5)^{-1} +(2012+\sqrt{2013^{0} })+81^{1/4}[/tex]

Answer 1

Respuesta:

D. x^3<-8

Explicación paso a paso:

5. If x=23^2*25^4*27^6*29^8 and is a multiple of 26^n, where n is a non-negative integer, then what is the value of n^26-26^n?

A. -26

B. -25

C. -1

D. 0

E. 1

n=0 because x is not a multiple of 26

n^26 - 26^n = 0-1 = -1

Option

Spoiler: ::

rijul007

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Re: NEW!!! Tough and tricky exponents and roots questions  [#permalink]New post 12 Jan 2012, 11:44

3

6. If x=\sqrt[5]{-37} then which of the following must be true?

A. \sqrt{-x}>2

B. x>-2

C. x^2<4

D. x^3<-8

E. x^4>32

x^5 = -37

-2^5 = -32

-3<x<-2

A. Eliminated

B. Eliminated

C. x^2<4 = -2<x<2 Eliminated

D. x^3<-8 Correct