Question

a) (-1/2)3.(-1/2)4.(-1/2)-2
b) (3/4)5.(3/4)-3 ÷(-3/4)-4
c) [(-7/8)7 ]-2.(-7/8)9 ÷(7/8)-3

Answer 1

$A) (- \frac{1}{2})^3.(- \frac{1}{2})^4.(-1/2)^{-2}= \quad aplicas \ propiedades \ de \ potencia \\ \\ (-1/2)^{3+4-2}=(-1/2)^{5}=- \frac{1}{32} \\ \\ \\ B) ( \frac{3}{4})^5.( \frac{3}{4})^{-3}:(-\frac{3}{4}) ^{-4}= \\ \\ ( \frac{3}{4})^{5-3}:(-\frac{3}{4}) ^{-4}= \\ \\ ( \frac{3}{4})^{2}:(-\frac{4}{3}) ^{4}= \frac{9}{16}: \frac{64}{81}= \frac{729}{1024}$

$C) [(- \frac{7}{8})^7 ]^{-2}(- \frac{7}{8}) ^{9} :( \frac{7}{8})^{-3}= \\ \\ C) [(- \frac{7}{8}) ]^{-14}(- \frac{7}{8}) ^{9} :( \frac{7}{8})^{-3}= \\ \\ C) [(- \frac{7}{8}) ]^{-14+9} :( \frac{7}{8})^{-3}= \\ \\ C) [(- \frac{7}{8}) ]^{-5} :( \frac{7}{8})^{-3}= \\ \\ C) [(- \frac{8}{7}) ]^{5} :( \frac{8}{7})^{3}= \\ \\ C) (- \frac{32768}{16807}) :( \frac{512}{343})=- \frac{64}{49}$

Espero que te sirva, salu2!!!!

Answer 2

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